Exercise Set Unit  IV

Applications of The Standard Normal Curve 

Find the area under the standard normal distribution:

1. between z =0 and  z =0.56 answer = 0.2123

2. between z =0 and z = -2.07 answer = 0.4808

3.to the right of z =0.23 answer = 0.4090

4.to the right of z = -0.18 answer = 0.5714

5.between z = 0.79 and z = 1.28 answer = 0.1145

6. between z = -1.03 and z = 2.47 answer =0.8417

Applications of The Normal Curve 

1. Suppose that the height of college women have a normal distribution with mean mu = 65 inches and standard deviation sigma = 2.7 inches. What is the probability that a randomly selected college woman is 62 inches or shorter? Answer = .1335

2.From the previous problem, find the probably that a college woman selected at random has a height greater than 68 inches. answer =  .1335

3.If test scores on a statistic exam are normal with mean = 100 and standard deviation sigma = 15, find the percent of scores that fall below 112. answer = 78.81%

4.The American Automobile Association reports that the average time it takes to respond to an emergency call is 25 minutes. Assume the variable is approximately normally distributed and the standard deviation is 4.5 minutes. If 80 calls are randomly selected, approximately how many will be responded to in less that 15 minutes? answer = 1.048 or approximately one call will be responded to in under 15 minutes.

5. In order to qualify for a police academy, candidates must score in the top 10% on a general abilities test. The test has a mean of 200 and a standard deviation of 20. Find the lowest possible score to qualify. Assume the test scores are normally distributed. answer =  226

Applications of The Central Limit Theorem

1.The average age of a vehicle registered in the United States is 8 years or 96 months. Assume the standard deviation is 16 months. If a random sample of 36 vehicles is selected at random, find the probability that the mean of their age is between 90 and 100 months. answer = .921

2.The average number of pounds of meat a person consumes in a year is 218.4 pounds. Assume that the standard deviation is 25 pounds and the distribution is approximately normal. Find the probability that a person selected at random consumes less that 224 pounds per year. answer = 0.5871

3. From the previous problem, if a sample of 40 individuals is selected, find the probability that the mean of the sample will be less than 224 pounds. answer = 0.9222

Confidence Interval Estimation

1.A study of 40 bowlers showed that their average score was 186. The standard deviation of the population of bowlers is 6. (a) Find a 95% confidence interval of the mean score for all bowlers. answer = [184.14,187.86] (b) Find a 95 % confidence interval of the mean score if 100 bowlers are used instead of  a sample of 40 answer = [184.76,187.23] (c) Which interval is smaller and why?

2.A random sample of 48 days taken at a large hospital shows that an average of 38 patients were treated in the emergency room per day. The standard deviation of the population is 4. Find a 99% confidence interval of the mean number of ER patients treated each day at the hospital. answer = [36.512,39.487]

3. Ten randomly selected automobiles were stopped, and the tread depth of the right front tire was measured. The mean depth was 0.32 inches, and the standard deviation was 0.08 inches. (a) Find a 95% confidence interval of the mean depth. Assume that that the variable is approximately normally distributed. answer = [0.26,0.38] (b) must the "t" distribution be used in this problem?

Minimum Sample Size to Estimate Population Mean MU

1.You want to estimate the mean weight of  squirrels  in your area.  How any squirrels must be included in your sample if you want to be 95% confident that the sample mean weight is within 1 ounces of the population mean? You know that the population standard deviation is 5 ounces.

Answer: the margin of error is one ounce, the critical z score is 1.96, and sigma =5 ounces. Calculating N:

Thus at least 96 squirrels should be included in your sample.